Solve. 1/3x+9-2/x+3=2
Where is the problem?
I believe that is the problem
Yes, but we need to know why she has doubts to solving it.
\[1\div3x+9-2\div x+3=2\] (the divison signs are supposed to be long like : ----
At what part you get stucked?
oh I don't understand how to solve it
\[1/(3x+9)-2/(x+3)=2\] Is it correct like this?
If the problem should look like marrioncito's then you get 1/2 as the answer.
Yes Marrioncito and thank you Ledah :)
Your welcome :)
\[1/(3x+9) =2 + 2/(x+3)\]
wait a second...... would the answer change if there were no parenthses, cause there are none in the problem
You got a different problem.
\[1/3x+9−2/x+3=2\] ?
yes
\[1/3x - 2/x = 2 -3 - 9 = -10\]
\[1/3x - 2/x = -5/3x = -10\] \[5/3x=10\] \[5=10.3x = 30x\] \[5 = 30x\] \[5/30 = x\] \[1/6 = x\]
Leda has not read that the problem was another one. Follow my steps, if you have questions just ask!
here I'm not sure you guys are getting the problem....let me draw it for you
I rewritted it like this: to Medals 0 1/3x+9−2/x+3=2
|dw:1337484404995:dw|
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