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Find the height.
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I get rt27.
solve the triangle: 6^2=h^2 + (3sqrt2)^2
\[\sqrt{27}?\]
hmmm maybe i'm wrong, i got somethin diffnt... i got 3sqrt2
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how?
the base is a square side 6 so the diagnol of that square is 6sqrt2 (45-45-90 triangle) half of that is 3sqrt2. the slant going up to the vertex of the pyrmid is 6 (that's your hypotenuse). the third side is the height, h. so 6^2=h^2 + (3sqrt2)^2 is what i used to find h.
Don't you need to split the triangle? |dw:1337487874941:dw|
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