Which of the functions could be represented by the graph shown?

Question

anonymous · Answer

I have the answer but don't understand why

anonymous · Answer

So wat hints do you have? The answers cant be negative.

anonymous · Answer

non of them!

anonymous · Answer

Well, you could try plugging in values and seeing what happens. Since on the graph $$f(\frac{\pi}{2})=0$$, if the function gives any other value it can't be that function.

$$\sqrt{\sin{\frac{\pi}{2}}}=1$$, so it can't be A

$$\sin^2(\frac{\pi}{2})=1$$, so it can't be B

$$\sin{\sqrt{\pi/2}}=0.95002...$$, so it can't be C

$$\sin((\pi/2)^2)=0.624...$$, so it can't be D

$$\sin{(\pi/(\pi/2))}=\sin{2}=0.909...$$
Is there a "none of the above" answer? This question seems flawed.

anonymous · Answer

3pi/2 doesnt exist on your graph

anonymous · Answer

Ans is