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Determine the slope of the secant line through the given x values: -3x^5+9x^3-7x+11, x=-7.3, x=11.2
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typo, this is better\[m=\frac{f(x_1)-f(x_2)}{x_1-x_2}\]
m is a common letter that is used to indicate slope
okay thanks. How would you find the slope of a tangent line through a given value of x? Example: f(x)=2x^2+6x-7, x=3
do you know what a derivative is?
yes
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the slope of the tangent line at a given point is the derivative of the equation using the given value of x to find its value
f'(x) = slope of tangent f'(3) = slope of tangent line at x=3
so for that example it would be 18 right?
2x^2+6x-7 4x+6 .... yep, 18 looks good
awesome thanks
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youre welcome, and good luck
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