Question

Can you determine the factors of x^2 - 8x - 12?

Answer 1

K so

Answer 2

any polynomial in form ax^2+bx+c can be factored by find the two numbers that multiply to give you c and add to give you b

Answer 3

1:SPLIT THE MID FACTOR
X^2+8X+12 EQUALS
X^2+6X +2X+12 [12=6*2
8=6+2]
2:TAKE COMMON FACTORS FROM 1ST TWO AND
LAST TWO FACTORS
X^2+6X +2X+12 EQUALS
X(X+6)+2(X+6)
3:TAKE (X+6) AS COMMON FACTOR
X(X+6)+2(X+6) EQUALS

(X+6){X+2}


PS:WHILE SOLVING QUADRATIC EQNS IN THIS FORM WHERE X^2 HAS NO COEEFICIENT U CAN DIRECTLY WRITE THE SOLN AS (X+6)(X+2)

Answer 4

so what two numbers multily together to give you -12 and add to give you -8

Answer 5

woah marco way to complicated

Answer 6

You have to use the quadratic equation.

Answer 7

guys.... you are making this so much more complicated then it needs to be

Answer 8

k im confused

Answer 9

Oh yeah that doesnt factor nicely

Answer 10

k ik its either (x - 6)(x + 2) or (x + 6)(x - 2) but idk which one

Answer 11

The way I mentioned actually fails in this case

Answer 12

so make use of the quadratic formula

Answer 13

but which one is (x - 6)(x + 2) or (x + 6)(x - 2)

Answer 14

Neither, it must be solved using the quadratic equation.

Answer 15

Right

Answer 16

Use b^2-4ac to determine whether it can be factored nicely if not use the quadratic formula