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prove sec(pi+x)=-sinx
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\[ \sec (\pi+x) = - \sec x\]
how do i prove it though?
help
\[ \sec x = \frac{1}{\cos x} \] \[ \cos ( \pi + x) = \cos \pi \cos x - \sin \pi \sin x = - \cos x \]
but i wanna find -secx..or is it the same?
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put \( \pi +x\) in place of x in sec in the above ...
so it this the answer then?
@hash.nuke is this the answer then?
yes
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