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Mathematics 18 Online
OpenStudy (anonymous):

PLEASE HELP!! A. Find x. B. is the triangle equilateral, isosceles, or scalene Picture: https://www.connexus.com/content/media/461958-3292011-34843-PM-1262076942/res00000/ppg/examview/S_GEOMB_06_06_06_Unit_6B_Test/sa012-1.jpg

OpenStudy (anonymous):

are those homeworks?

OpenStudy (anonymous):

its problrems i dont understand

OpenStudy (anonymous):

several easy problems !!they gona be assignment?

OpenStudy (zepp):

|dw:1337554586201:dw| A whole revolution is 360 degrees, you can find x by adding up everything and set it equal to 360. \((8x-10)+(6x)+(10x+10)=360\)

OpenStudy (anonymous):

x is 15 right

jimthompson5910 (jim_thompson5910):

you got it, x = 15 is correct Now use this to find the angle measures of the triangle

OpenStudy (zepp):

\((8x−10)+(6x)+(10x+10)=360\) Break up the parentheses. \(\begin{align} 8x-10+6x+10x+10&=360 \\ 24x&=360 \\ x&=15 \\ \end{align}\) Yup that's right :)

OpenStudy (anonymous):

what kind of triangle is it though?

jimthompson5910 (jim_thompson5910):

are you familiar with the inscribed angle theorem?

OpenStudy (anonymous):

no

jimthompson5910 (jim_thompson5910):

the idea is that the angle PQR is half of the central angle POR where O is the center point of the circle

jimthompson5910 (jim_thompson5910):

the central angle POR is equal to the arc measure of PR, so arc PR = 6*15 = 90 which means that m < PQR = (1/2)*90 = 45 This means that angle PQR is 45 degrees

OpenStudy (zepp):

|dw:1337555206881:dw| Like this :)

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