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Find the depressed polynomial of (x^3+4x^2-3x-5)÷(x+3) Please see if I found the correct answer
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I know what depressed people are but not depressed polynomials.
The answer I found was x^2+x-6+13/x+3 Is that the correct answer?
So, am I right? Your chart confuses me.
Thats long division \[x^2+x-6+\frac{13}{x+3}\]
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Awww, darn. I don't know what to do.
Simplified you'll get \[x^2+x-6+\frac{13}{x+3}\]
So, that's the right answer?
yes
Thank you for your help.
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