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how to find x in x^2-x-1 ?
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As is, you do not have an equation. What is that expression equal to?
to 0
|dw:1337559134977:dw| i found x
The quadratic formula seems like a good candiate. OMG lgbasallote has already found x!
teachers should phrase it as solve for x :P find x is tooo easy (unless x happens to be wally)
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that was not helpful at all , but I understand your point
on a helpful note though...use either completing the square or q.f.
it is not factorable...i can give you that
\[x ^{2}+x-1=0\]A=1 B=1 C=-1 Use quadratic formula.
C would be +1, when you move it to the other side of the equation
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x=[-1+/-sqrt(1+4]/2 \[=(-1\pm \sqrt{5})/2\]
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