Question

can someone please explain to me how you do something like(a-1)(a+1)(n^2+1)? I'm only in year 7 so I've only done (a-1)(1+1) and i know thats called quadratics but when there's 3 brackets, what is it called?
Thanks a lot :D

Answer 1

\[(a-1)(a+1)(n^2+1)\] or \[(n-1)(n+1)(n^2+1)\]??

Answer 2

second one

Answer 3

just make it n

Answer 4

\[(n−1)(n+1)(n^2+1)\]
We know:
\[(n-1)(n+1)=(n^2-1^2)=(n^2-1)\]

\[(n^2-1)(n^2+1)=(n^4-1^2)=(n^4-1)\]

Answer 5

shouldnt (n-1)(n+1) be n^2-1?

Answer 6

It is.

Answer 7

but u said (n-1)(n+1)=(n^2+1^2)

Answer 8

I said (n^2-1^2) and 1^2=1*1=1