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solve equation using the quadratic formula \[x^2+4x=7\]
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\[4\pm \sqrt{4^2+8(1)(7)}\] over 2
i cant seem to figure out how to make it a fraction thing
fraction is like this btw frac{num1}{num2}
ok i got that part , im just making sure i am on the right path
@cgian66 it shoulds be -4ac
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ty bitmaximus
re check your formula
@cgian66 -4ac
k
got it -4ac
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\[4\pm \frac{\sqrt72}{2}\]
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