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Mathematics 8 Online
OpenStudy (anonymous):

See equation.

OpenStudy (anonymous):

\[1/4=64^{2x-1}\]

Parth (parthkohli):

64 = \(4^3\), agree?

OpenStudy (anonymous):

you can use ln

OpenStudy (anonymous):

yes

Parth (parthkohli):

\(\Large \color{MidnightBlue}{\Rightarrow 64^{2x - 1} = (4^{3})^{2x - 1} = 4^{6x - 3} }\) And \(\Large \color{MidnightBlue}{\Rightarrow {1 \over 4} = 4^{-1} }\) Now, as the bases are equal, then we can make an equation of the exponents. \(\Large \color{MidnightBlue}{\Rightarrow 6x - 3 = -1 }\) \(\Large \color{MidnightBlue}{\Rightarrow 6x = 2 }\) \(\Large \color{MidnightBlue}{\Rightarrow x = {2 \over 6} = {1 \over 3}}\)

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