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Mathematics 8 Online
OpenStudy (anonymous):

What is the equation of the attached graph?

OpenStudy (anonymous):

OpenStudy (shubhamsrg):

i have a doubt,,does the graph cut -y axis somewhere or goes to -infinity at x=0 ?

OpenStudy (anonymous):

1/x is the equation -1/x + c i leave it to you to find c :P

OpenStudy (anonymous):

not sure it is 1/x @timo86m

OpenStudy (angela210793):

i don't think the equation is 1/x i think it is y=log x see the point (1:0)

OpenStudy (anonymous):

ah yex

OpenStudy (anonymous):

I was thinking of her other post

OpenStudy (anonymous):

sorry *blush*

OpenStudy (anonymous):

Hehe

OpenStudy (anonymous):

Its all good! =) My guess is f(x)=1/2log(x) is that correct?

OpenStudy (angela210793):

see u have log10=2 maybe it is y=2logx????

OpenStudy (anonymous):

Okay =) So you believe the answer I should be getting in f(x)= 2log(x)

OpenStudy (angela210793):

tht was just a though...Being honest I'm not sure

OpenStudy (anonymous):

Oh okay =) Thank you for an educated guess!

OpenStudy (angela210793):

ur welcome lol :P

OpenStudy (anonymous):

@dpaInc is the equation for this graph f(x)=2log(x)?

OpenStudy (anonymous):

u there?

OpenStudy (anonymous):

Yep =) It finally reconnected

OpenStudy (anonymous):

yeah... i'm getting the aw snaps from google chrome...

OpenStudy (anonymous):

it looks like your graph goes through (1,0) and (3, 1) you agree?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

then it's definitely not y=2logx

OpenStudy (anonymous):

i'm trying to come up with an explanation of how to get the answer..

OpenStudy (anonymous):

this is my answer btw... y=(1/ln3) * lnx

OpenStudy (anonymous):

Okay =) I have four options given, one of which is f(x)=3log(x), that was my second guess. Is that correct then? =)

OpenStudy (anonymous):

no not that one... that one makes the graph climb faster.. that's what the 3 does...

OpenStudy (anonymous):

what are your other choices?

OpenStudy (anonymous):

f(x)= 1/2 log(x) or f(x)=4log(x) are the options left

OpenStudy (anonymous):

oh wait.... this is log base 10!!!

OpenStudy (anonymous):

hope your not mad.... your original answer is correct y=2logx \[\huge SORRY!!!\] :(

OpenStudy (anonymous):

Thats totally okay! I really appreciate all your help, I am just glad we agree on an answer!! =) lol

OpenStudy (anonymous):

yeah... i usually work with ln and not log base 10... good work simmer...:)

OpenStudy (anonymous):

i mean swimmer..

OpenStudy (anonymous):

Plots are attached.

OpenStudy (angela210793):

So I was right

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