If M is the product of all integers from 1 to 50 which a factor 2^n...then the maximum value of n is
?????
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OpenStudy (anonymous):
is it 47
OpenStudy (anonymous):
use greatest integer function for all and then add [50/2] +[50/4]+[50/8]+[50/16]+[50/32]=25+12+6+3+1
OpenStudy (anonymous):
@shubhamsrg going thorugh NEST2010
OpenStudy (anonymous):
yeah xactly!
u toooo givin nest!
?
OpenStudy (anonymous):
no dear...
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OpenStudy (anonymous):
so u do u knw?
OpenStudy (anonymous):
xams are near thats why asked
OpenStudy (anonymous):
good
lust/love for maths is mportant for these kind of xams
best of luck....
OpenStudy (shubhamsrg):
well,,
1*2*3*4...50 = 1*2*3*(2*2)*....25*(13*2)*27*(14*2)*29*(15*2)....49*(25*2)
=(1*2*3*4...25)^2* (2^25 )..solving the inner bracket,,you get 2^12 outside..doing again,,you get 2^6 outside..you finally get what @matricked said!!
OpenStudy (anonymous):
no not like that
u get the abv rules in most of the text books
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OpenStudy (shubhamsrg):
this was just another method,,am sure there must be many such,..