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OpenStudy (anonymous):
show that\[\sum_{n=0}^{\infty}((n!)^{2}2^{n+1} / (2n+1)!) =π\]
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OpenStudy (anonymous):
See http://math.stackexchange.com/questions/77607/how-to-sum-this-series-for-pi-2-directly There are several methods to show your identity.
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