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Another differentiability problem:)
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If \[f(x)=a^x\] is a differentiable function. then why is it truly differentiable for only "a>0".
@apoorvk plz help:)
for a negative no, when 'x' changes form odd to even, the function switches from negative to positive rapidly. - so it has a lot of sharp points - hence it's not differentiable.
K! thanx.
d/dx of a^x is equal to a^x log(a) which is another general rule....
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Thanx to u too.
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