can you help me with this for my exercises:

I need to to show that:
g(x)= (e(-3x+2sinx)/6)
----------------
(3+2cosx)

has derivative

g'(x)= - (4(sin^2)x -12sin x +5) (e(-3x+2sinx)/6)
-----------------------------------
6(3+2cosx)^2

Question

can you help me with this for my exercises:

I need to to show that:
g(x)= (e(-3x+2sinx)/6)
           ----------------
                (3+2cosx)

has derivative

g'(x)= - (4(sin^2)x -12sin x +5) (e(-3x+2sinx)/6) 
              -----------------------------------
                                    6(3+2cosx)^2

anonymous · Answer

$$d(u/v)=(v*u'-v'*u)/v^2$$ try this

chaise · Answer

The above is right, but also try re-write your equation like this: then applying what nageswar has used (the quotient rule)

$$\frac{e(2\sin(x)-3x)}{6(2\cos(x)+3)}$$.

I think you will find that dy/dx in this equation is not the equation given (the derivative of sin(x) is cos(x) which has not changed in the equation at all. Unless you have written the question wrong or I am misinterpretting it.