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Solve radical equation. If there is no solution, write no solution. Uploaded question BELOW (: thanks
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HERE IS THE QUESTION
2x = sqrt (3x + 1)
@apoorvk
I ^2 both sides and then subtracted 3x and 1 from each side. Then I tried factoring but it's unfactorable?? What do I do
just square both sides
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I did.. then what is the next step?
\[4x^2 = 3x+1\] then 4x^2 -3x -1=0
gets??
then factor
(4x+1)(x-1)=0
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x = 1
x=1 and x=-1/4
@KieraJan did you know how to solve it??
now I do.. so the answer is one solution?
because I plug them in to original equation to check, right?
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and when they equal out.. it's considered a solution
Only one equals out sooo is it one solution???
I think so
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