Question

1. You roll a number cube once. Then you roll it again. What is the probability that you will get a 6 on the first roll and a number greater than 3 on the second roll?
1/12,1/6,2/3,1/9

Answer 1

P(Getting a 6) = 1/6
P(Getting n>3) = 1/2

P(Getting both) = \(\Large \color{MidnightBlue}{\Rightarrow {1 \over 6} * {1 \over 2} = {1 \over 12} }\)

Answer 2

the possible outcomes for such an event are given by 6^( no of dice or throws)=6^2=36
Now you have to use your brain. There will be only one case in which you wil get a 6 on the first dice and three cases where you will get a six on the first dice and 4,5,6 on the other =3events, so the probablity =3/36=1/12