Question

2(6+x)-8(5-x)=-48

Answer 1

you should distribute first

Answer 2

odalys distribute like i showed you last time

Answer 3

12+2x-40+8x=-48
18x=98
x=5.4
is this right?

Answer 4

yeay i think this is about it.

Answer 5

"i think" dont sound like a sure answer, but thanks for your help :)

Answer 6

i mean this IS THE RIGHT ANSWER :)

Answer 7

\[2 (6+x) - 8 (5-x) \text{ =} -48\]\[-28+10 x=-48\]x = -2

Answer 8

ok :) thanks

Answer 9

you just confused me robtobey :/

Answer 10

where did you get -28+10x from?

Answer 11

your distribution was correct but somewhere your adding of like terms went wrong

Answer 12

we'll start from your distribution

12+2x-40+8x=-48

Answer 13

if you combine like terms on the left side you get

\[(12-40)+(2x+8x)=-48\]

Answer 14

this is where

-28+10x=-48 comes from

Answer 15

ok got it. so now i add -28+10x?

Answer 16

Constants can always be combined

Variables are a little different they must have the same varible and power so

4x+2x=6x

but

\[x^2+x\] CANNOT BE COMBINED

same with

x+y CANNOT BE COMBINED

Answer 17

so you have -28+10x=-48

you want to isolate -10x on one side and eventually get x=?

Answer 18

what can you do to both sides to get 10x on the left side by itself (isolation of x term)