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If the Discriminant of an equation is negative, which of the following is true of the equation
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if this is quadratic then discriminant >0 then two real roots discriminnt = 0 1 real root discriminant < 0 complex roots
which two values of x are roots of the polynomial below x^2 + 5x + 9
you can do this in two ways 1) Sick it into the quadratic formula.\[x= (-b \pm \sqrt{b ^{2} - 4a2}) \div 2a\] 2) try to factorise where you wor out all the factors of nine and the two that add to +5 is the anwer
Ill show you
\[(-5+\sqrt{-11})\div2 \] \[(-5-\sqrt{-11})\div2 \] because 5^2 - 4x1x9 is negative so it has no real roots
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hmm the quadratic eqn is wrong should be :\[(-b \pm \sqrt{b^2-4 \times a \times c})\div 2 \times a\]
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