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What is the slope of a line that passes through the point (−5, 3) and is parallel to a line that passes through (2, 13) and (−4, −11)?
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So, first use the two points to find the slope.
Slope is\[(y _{2} - y_{1})\div(x_{2}-x_{1})\]
So, 13+11/2+4 = 24/6=4.
So, the line is y=4x+b, but we need the y-intercept. To do this, we plug in a point.
Plugging in (-5,3), we have 3=4(-5)+b, or b=23.
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So the line is y=4x+23.
okay so the slop would be 4 correct?
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