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Solve 4^x=20 Round to the nearest ten thousandth
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do you know how to convert it to logarithmic form?
No.. my teacher sucks. :)
lol
take log number on log the base and it will be x=log20/log4
\[4^x=20\] \[x \log 4 = \log 20\] \[x=\frac{\log20}{\log 4}\] Basically, log both sides. Usually the log rule, you can take the exponent x and place it as a coefficient. Then divide both sides to solve for x.
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Okay
lol when i said change to log form i meant \[\LARGE a^x = b \Longleftrightarrow \log_a b = x\]
Ohh I think I learned that. I think. lol
well you end up with \[\large \frac{\log 20}{\log 4}\] anyway..have you learned that?
yea.. I think so. But we learn stuff so quick i never get a chance to fully understand.
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I got the answer now :)
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