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\[\frac{x}{x-4}+\frac{6}{x+4}=\frac{x(x+4)+6(x-4)}{(x+4)(x-4)}\] \[=\frac{x^2+4x+6x-24}{(x+4)(x-4)}=\frac{x^2+10x-24}{(x+4)(x-4)}\] is a start. i can't read the rest of it, but it looks like a division if so, invert and multiply just like with numbers
ok thank you soo much! :)
yw i am sure that you will be able to factor and cancel something, the problems are always cooked up that way
yes i can :) so the answer would be |dw:1337650153270:dw| ???
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