Question

The length of the base of the triangle is b, the length of the corresponding altitude is h, and the area is A. Find the missing part.

base is 2 square root of 3
height is 3 square root of 3
what is the area in. sq. in.

Answer 1

area is the base times the height divided by two

Answer 2

so it's \[(2\sqrt{3})\times(3\sqrt{3})/2\] = \[18/2 = 9\]

Answer 3

how did you get 18

Answer 4

2x3 = 6
\[\sqrt{3}\times \sqrt{3} = 3\]
6x3 = 18

Answer 5

okay so u have to break the quare root down too

Answer 6

yeah

Answer 7

if you had another problem your base is ____________ your height is 5 and your area is 10 square inches I would have thought your base would be 2 but it keeps saying its wrong do you know what i am doing wrong

Answer 8

\[\large A = \frac{bh}{2}\] \[\large 2A = bh\] \[\large \frac{2A}{h} = b\]

Answer 9

^what @igbasallote is saying is that you have to multply by two to take the half factor into account

Answer 10

so your answer is 4

Answer 11

yup

Answer 12

The lengths of the sides of a right triangle are a and b, and the hypotenuse is c. Find the area of the triangle.

a = 6 in.; b = 4 in. A = sq. in I know there is a special formula for this one I cant remember which one it is , can you help with this