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The lengths of the sides of a right triangle are a and b, and the hypotenuse is c. Find the area of the triangle. A = 2/3 ft.; c = 4 ft. A = sq. ft.
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|dw:1337656774870:dw|
Area of a triangle \[A=\frac12 bh\]
area = bh/2 b is the base length h is the height here a is your base and b is your height so you should get (1/2)(2/3)(4) =4/3
@cerezas, where did you get the value for b?
misread c>.< but you can use pythagoras to find it
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4^2 - (4/3)^2 - b^2 16 - 16/9 = b^2 b^2 = 128/9 b = 8(sqrt(2))/9
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