Question

In an electrical circuit, the current passing through a conductor varies inversely with the resistance. Suppose that when the current is 10A(amperes), the resistance is 14 ohms. What is the current when the resistance is 5 ohms?

Answer 1

well i = k/r (k=constant)
thus ir = constant
so i1 * r1 = i2 * r2 ..
hope this'll help

Answer 2

Using standard ohm's-law speak. I = current, R = resistance, V = voltage:
\[10A * 14 \Omega = 140V\]\[ I * 5 \Omega= 140V\]\[I=28A\]