Find the length of the legs of a 45°-45°-90° triangle with a hypotenuse ofhttps://www.connexus.com/content/media/102878-7212005-21133-PM-975010522.gif.

Question

anonymous · Answer

Find the length of the legs of a 45°-45°-90° triangle with a hypotenuse of $$4\sqrt{2}cm$$

anonymous · Answer

divide by $\sqrt{2}$ and get 4

anonymous · Answer

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anonymous · Answer

pythagoras tells you that 
$$x^2+x^2=h^2$$
$$2x^2=h^2$$
$$\sqrt{2x^2}=h$$
$$\sqrt{2}\times x=h$$ so to get from the length of the leg to they hypotenuse, multiply by $\sqrt{2}$ .  to go the other way, divide by $\sqrt{2}$

parthkohli · Answer

Well, the ratio of a 45-45-90 triangle is:


$\Large \color{MidnightBlue}{\Rightarrow x,x,x\sqrt{2} }$

Where x root 2 is the hypotenuse. Hope you have got the hint till now.