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The product a^(logb-logc) *b^(logc-loga)*c(loga-logb) equals?
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@saifoo.khan @satellite73 @glgan1 @guykubpom @ajprincess
@FoolForMath
ummm use the property that a^logb = b^loga then the answer will become 1 :)
s the answer is 1 plzz can u show it.....
is that c^(loga-logb) ??
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a^logb = b^loga then it will disappear by b^(-loga) do like this 3 times :))
@ujjwal @dumbcow @dpaInc @Diyadiya @ash2326 @kelly_01 @ArchiePhysics @eSpeX @experimentX plzz help
use the technique mentioned above to simplify things ... \[ \huge a^{\log b} = b^{ \log a}\]
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