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Mathematics 24 Online
OpenStudy (anonymous):

The product a^(logb-logc) *b^(logc-loga)*c(loga-logb) equals?

OpenStudy (anonymous):

@saifoo.khan @satellite73 @glgan1 @guykubpom @ajprincess

OpenStudy (anonymous):

@FoolForMath

OpenStudy (anonymous):

ummm use the property that a^logb = b^loga then the answer will become 1 :)

OpenStudy (anonymous):

s the answer is 1 plzz can u show it.....

OpenStudy (experimentx):

is that c^(loga-logb) ??

OpenStudy (anonymous):

a^logb = b^loga then it will disappear by b^(-loga) do like this 3 times :))

OpenStudy (anonymous):

@ujjwal @dumbcow @dpaInc @Diyadiya @ash2326 @kelly_01 @ArchiePhysics @eSpeX @experimentX plzz help

OpenStudy (experimentx):

use the technique mentioned above to simplify things ... \[ \huge a^{\log b} = b^{ \log a}\]

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