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What is the solution set of x^2 + 5x - 5 = 0?
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\[x= [-5 \pm \sqrt{(5^2) - 4(1)(-5)} ] \div 2(1)\]
so you will get x=\[[-5 + 3\sqrt{5} ] /2 \] and \[[−5-3\sqrt{5}] /2\]
ok thank you
btw sweet pic
do you know the formula to find solutions which is \[[-b \pm \sqrt{b^2 - 4ac} ] /2a\] use this formula whenever u cant factorize the equation. a is the coefficient of x^2, b is the coefficient for x and c is the constant. lol thanks. :)
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