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Find the next three terms of the following sequence
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\[3, \frac{10}{3}, \frac{11}{3}, ...\]
This is A.s where a=3 ,d=1/3 where a is the first term and d is the difference between every term .. So u want the next three terms u have 2 ways 1st way : to add 1/3 to the last term and so on ... 2nd way : to substitute in the rule Tn=a+(n-1)d ex: T4=3+3*1/3=4 and so on.... _____ U get it ?
I'm still confused?
I need to find the 20th term of the sequence, too.
Do u know the rule of the nth term which is Tn=a+(n-1)d
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Would the next three terms be \[4, \frac{13}{3}, \frac{14}{3}\] Am I correct?
Thats totally right ,Gj :)
Now I will try to find the 20th term.
Would the 20th term be \[\frac{28}{3}\]
right Gj
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Thank you :)
yw ..
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