Question

which is the equation with slope 5 that contains point (-2,-3)
a.y-3=5(x-2)
by+2=5(x-3)
c.y+3=5(x+2)
d.y-2=5(x-3)

Answer 1

\(\Large \color{MidnightBlue}{\Rightarrow y = 5x + b }\)

Let's substitute.
\(\Large \color{MidnightBlue}{\Rightarrow -3 = 5(-2) + b }\)
\(\Large \color{MidnightBlue}{\Rightarrow -3 = -10 + b }\)
\(\Large \color{MidnightBlue}{\Rightarrow 7 = b }\)

So, the equation is:
y = 5x + 7

Answer 2

Those previous equations are in slope intercept form. The answer choices are in point-slope form (which is arguably easier to deal with since you only take one step really)


y - y1 = m(x-x1)


y - (-3) = 5(x - (-2) ) .... Plug in x = -2, y = -3 and m = 5


y + 3 = 5(x+2) ... Rewrite x-(-2) as x+2 and y-(-3) as y+3


So the equation in point-slope form is y + 3 = 5(x+2)

Answer 3

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Answer 4

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