Question

simplify 12x^(-3)y^(2)/18xy^(-1)

Answer 1

\[12x ^{-3}y ^{2} / 18xy ^{-1}\]
First step is to simplify 12/8, which is 3/2
Next look at your exponents abouve your x's and y's. Since you have exponents set in a fraction, you subtract your exponents above the x's, then subtract the exponents above the y's
\[x ^{-3-1}= x ^{-4}\]
\[y ^{2-1} = y ^{3}\]
Now you have 3/2 x^-4y^3
since x has a -4 as an exponent, you bringiing x^-4 down to be with the denominator which is 3. You leave y^3 up with the numerator of 2.

Answer 2

I hope this helps!