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What is the third term of (a+b)^11
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(r+1)th term = nCr a^(n-r) b^r
here r = 2, n = 11 3rd term = 11C2 a^9 b^2 - can you continue from here?
11C2 a^9 b^2 is the answer?
well we need to calculate 11C2 - which is the number of combinations of 2 in 11 = 11* 10 ----- = 55 2 * 1 sao 3rd term is 55a^9 b^2
Thank you for your help
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