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6* 8^(x+1) = 2^x
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take ln of both sides
i know that but i could do anything after taking the ln
well you might wanna use change of base formula to get the bases to same base
so there is 6 time 8 on exponent ... ?
or what is 6 there ?
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it is just 6 times 8 exponent of x+1
can you writing 8 like power of 2 , 2 on exponent ?
what ?
Easier way: manipulate it a bit first.\[ 6\cdot8^{x+1}=2^x\\ 6\cdot8\cdot8^x=2^x\\ 48\cdot2^{3x}=2^x\\ 48=\frac{2^x}{2^{3x}}\\ 48=2^{-2x}\\ -2x=\log_248 \]
You can finish it from there, right @Williamskates ?
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ok but where is 2^x from numerator ?
yeah thanks
@jhonyy9 i dont know what are you taking about dude
ok i see it now ,is right
good luck bye
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