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Mathematics 18 Online
OpenStudy (anonymous):

The slope of the line normal to the curve e^x − x^3 + y^2 =10 at the point (0, 3) is: A. −1/6 B. 1/6 C. 6 D. − 6 E. Undefined

OpenStudy (anonymous):

@dpaInc

OpenStudy (anonymous):

@saifoo.khan

OpenStudy (saifoo.khan):

@precal

OpenStudy (saifoo.khan):

we have to find dy/dx and then put x = 0

OpenStudy (anonymous):

so....e^x − x^3 =-y^2 +10, then take derivative?

OpenStudy (saifoo.khan):

First we have to make y the subject? sorry im not sure.

OpenStudy (precal):

I think you just sub 0 and get the slope then since they want the normal line, take the opposite reciprocal of that slope

OpenStudy (anonymous):

@precal I got -2, but that's not an option

OpenStudy (precal):

ok let us see, I am going to put pencil to paper, I was doing the lazy approach above

OpenStudy (precal):

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