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The slope of the line normal to the curve e^x − x^3 + y^2 =10 at the point (0, 3) is: A. −1/6 B. 1/6 C. 6 D. − 6 E. Undefined
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@dpaInc
@saifoo.khan
@precal
we have to find dy/dx and then put x = 0
so....e^x − x^3 =-y^2 +10, then take derivative?
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First we have to make y the subject? sorry im not sure.
http://www.wolframalpha.com/input/?i=find+the+derivative+of+e%5Ex+%E2%88%92+x%5E3+%2B+y%5E2+%3D10+
I think you just sub 0 and get the slope then since they want the normal line, take the opposite reciprocal of that slope
@precal I got -2, but that's not an option
ok let us see, I am going to put pencil to paper, I was doing the lazy approach above
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