The slope of the line normal to the curve e^x − x^3 + y^2 =10 at the point (0, 3) is:

A. −1/6
B. 1/6
C. 6
D. − 6
E. Undefined

Question

The slope of the line normal to the curve e^x − x^3 + y^2 =10 at the point (0, 3) is:

A.	−1/6
B.	1/6
C.	6
D.	− 6
E.	Undefined

anonymous · Answer

@dpaInc

anonymous · Answer

@saifoo.khan

saifoo.khan · Answer

@precal

saifoo.khan · Answer

we have to find dy/dx and then put x = 0

anonymous · Answer

so....e^x − x^3  =-y^2 +10, then take derivative?

saifoo.khan · Answer

First we have to make y the subject? 

sorry im not sure.

precal · Answer

precal · Answer

I think you just sub 0 and get the slope
then since they want the normal line, take the opposite reciprocal of that slope

anonymous · Answer

@precal I got -2, but that's not an option

precal · Answer

ok let us see, I am going to put pencil to paper, I was doing the lazy approach above

precal · Answer

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