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Let f(x) be the function defined by f(x) = 2x^3 - 3x^2 - 12x + 20. a) Write an equation defined by the line normal to the graph of f(X) at x=0 b) Find the x and y coordinates of all points on all the graph of f(x) where the line tangent to the graph is parallel to the x-axis. c) Sketch the graph of f with the line tangent to the point that you found from part b.
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1) take the derivative 2) replace \(x\) by 0 ( you will get -12) 3) normal line will have a slope that is the negative reciprocal \(\frac{1}{12}\) 4) use the point slope formula to find the equation of the line
and how to do part b?
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