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Because the two triangles are similar we know that \[\frac{3}{x+1}=\frac{7}{3x-1}\]Solve for x.
i got confused similar in terms of? shape?
Since both triangles are similar, that means to shows that the sides of the triangle are equal IN PROPORTION. *note, they are not equal in value, they are equal only in proportion. Thus equating the proportionality, \[\frac{x+1}{3}= \frac{3x-1}{7}\] 7(x+1) = 3( 3x-1) 7x+7 = 9x-3 2x = 10 x= 5. Thus side 3x-1 is equals to 14.
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thank you
pfeen1 can you help me with another one
sure. If I can
This is set up exactly like the other one. See if you can set up the relationship.
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