Find the value of 3 over the square root of 3..
thats 27 3*3*3 = 27
\[\frac{3}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} \]
^that's called 'rationalizing' :)
There are 2 ways to go about this question, depending on what the question really wants. You can punch everything into the calculator to give you an approximate value, 3/ sqrt(3) = 1.73 approx. Or the question actually requires you to rationalize the expression. Given 3/ sqrt(3), you multiply sqrt(3) to both the numerator and denominator, giving just sqrt(3).
A. 3 B. 3 times the square root of 3. C. the square root of 3. D. the square root of 3 over 3. ???
c) but do you understand how you got the answer?
i think
Find the value of 10 times the square root of 2 over the square root of 5. Choose one answer. A. 2 B. 2 times the square root of 5. C. 2 the square root of 10. D. 2 over 5 times the square root of 10.
Just like before you need to rationalize it, do you remember how to rationalize?
the answer is B RIGHT
now you are just guessing, and that's not good. If you have a square root in the denominator, do you know how to get it into the numerator: hint: same as the last question you asked.
rAtionalize
yup, so how would you rationalise? \[\frac{10\sqrt{2}}{\sqrt{5}} \]
hint: you need to multiply it by something. Same way we did in the last question
still on this question?
yes 2 diveded by 10 than 5 times 5?
@dahmanman you gave him the wrong answer to the first question
hats the answer than
@suzukirider1400 yes! 10 square root 2 divided by square root 5 times square root 5 divided by the square root five, or: \[\frac{10\sqrt{2}}{\sqrt{5}} \times \frac{\sqrt{5}}{\sqrt{5}}\] so now what should we do?
let's start in the denominator. do you know what: \[\sqrt{5} \times \sqrt{5} = ?\]
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