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what is the common difference for the geometric sequence 4, 12, 36
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A geometric sequence is of the form \[a, ar, ar^2...ar^n\] Two consecutive terms are in the same ratio that is \[\frac{ar}{a}=\frac{ar^2}{ar}=\frac{ar^3}{ar^2}=r\] here r is the common difference or ratio so here we have 4, 12 and 36 so \[\frac{12}{4}=\frac{36}{12}\] Can you find this?
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yeah no i get it it 3*4=12*3=36 and so on
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