Question

what is the asymptote for the hyperbola... ?
(y+1)^2 (x+4)^2
________ _ ________
300 48

Answer 1

can anyone e help?

Answer 2

\[y-C_y=\pm\sqrt{\frac{b^2}{a^2}}(x-C_x)\]

Answer 3

so... would it be \[\pm(1/4)(x+4)+1\] ?

Answer 4

since this thing never touches the "x" axis; a^2 is under the y part and the b^2 is under the x part;

Answer 5

is that a guess from the answer options? or did you try to work that out?

Answer 6

i tried to figure it out... but i really don't understand...

Answer 7

the asymps run thru the center so we want that point on our line; the slope is defined as .... hmm, sqrt(ypart/xpart) now that i think of this