Question

simplify and write in standard form
-y(8y^2+y)

Answer 1

Just distribute.


\(\Large \color{MidnightBlue}{\Rightarrow a(x \pm y) = ax \pm ay }\)

Answer 2

distribute... \[\large -y(8y^2) + (-y)(y)\]

Answer 3

So it would be -8y^3+y^2

Answer 4

-y^2

Answer 5

Yes, right.

Answer 6

it should be \[\large -8y^3 - y^2\] @keegq