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factor the expression x^2-6x+5
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break down the middle term into \[x^2 - x - 5x + 5x\]
then do the -5x + 5X cancel out?
|dw:1337837484141:dw|
oops lol that's supposed to be \[\large x^2 - x - 5x + 5\]
You have to think of "something multiplied by something' and get 5 and that "something also add up to -6
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So the answer would be x^2-6x+5
isnt that the question lol
\[\large (x^2 - x) + (-5x + 5)\] factor it out
Oh I see now thanks
so you can do the rest now?
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No does it need to break down more?
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