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1 + |1/3a| = 4 help find solution ? >.<
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step 1 take one from both sides
is the 'a' part of the fraction or not?
it's a variable aside
\[\left|\frac 13a\right|=3\]\[\frac 1 3\left|a\right|=3\]\[|a|=1\]\[a=\pm1\qquad=1,\quad -1\]
um not really no
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\[\text {iff }|a|=9\]\[a=9\qquad\text{or}\qquad a=-9\]
Sorry, but also your answer of +1 and -1 was not right? I was thinking that a^2 =9
oh i see a mistake in my working \[\frac{1}{3}|a|=3\]\[3\times\frac{1}{3}|a|=3\times3\]\[|a|=9\] sorry about that
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