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\[\frac5z+\frac32_z= -1\]
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at the bottom there its 2z but i didnt know how to write it...
First, multiply the \(5\over z\) by \(2\over2\). Now that you have a common denominator, add the two to get \[\frac{10+3}{2z}=-1\]
Can you solve for \(z\) from there?
Can I multiply both sides by 2z to get rid of the denominator 2z?
That's exactly what you want to do.
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then divide both sides by -2 to isolate z, so z=-13/2..?
Perfect.
Woo! Thanks :D
You're welcome.
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