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Mathematics 19 Online
OpenStudy (anonymous):

solve 2|3(x-5)|+3=9

sam (.sam.):

12|3(x-5)|+3=9 Move 6 to RHS 2|3(x-5)|=6 Divide each term in the equation by 2. |3(x-5)|=3 Remove the absolute value term. This creates a +- on the right-hand side of the equation because |x|=+-x. \[3(x-5)=\pm (3)\] Try to solve from here

OpenStudy (anonymous):

thanks sam

sam (.sam.):

welcome :)

OpenStudy (anonymous):

@DezzieDay check your answer

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