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solve 2|3(x-5)|+3=9
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12|3(x-5)|+3=9 Move 6 to RHS 2|3(x-5)|=6 Divide each term in the equation by 2. |3(x-5)|=3 Remove the absolute value term. This creates a +- on the right-hand side of the equation because |x|=+-x. \[3(x-5)=\pm (3)\] Try to solve from here
thanks sam
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