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find values of x for which f(x)=g(x) f(x)=x^2+2x+1, g(x)=3x+3
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@.Sam.
@Callisto
can you show me the steps please?
all you need to do is solve x^2+2x+1 = 3x+3 put it in standard form: x^2-x-2 = 0 subtracted 3x+3 from both sides and simplified. (x+1)(x-2)=0 factored you can take it from here. the answer is now obvious.
Equate them together and solve since f(x)=g(x) x^2+2x+1=3x+3
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so the values would be like 1 and -2?? im confused.
@.Sam.
no, from here, (x+1)(x-2)=0 you set each brackets =0, (x+1)=0, (x-2)=0 then solve for 2 values of x
ohh so -1 and 2 thank you! :)
yes
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thanks sam! :)
welcome :)
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