Brennan is making a poster for the drama club’s new production. It is a regular pentagon with side lengths of 12 inches. The school wants to put up a giant replica of the poster during athletic events.

If the length of each side is 8 times the original, how many times larger is the area of the replica than the area of the original?
Answer

Question

Brennan is making a poster for the drama club’s new production. It is a regular pentagon with side lengths of 12 inches. The school wants to put up a giant replica of the poster during athletic events.

If the length of each side is 8 times the original, how many times larger is the area of the replica than the area of the original?
Answer

shubhamsrg · Answer

well area of a pentagon for a side a = 6 * sqrt(3) * a^2 /4
i.e area is proportional to a^2..
if each side gets 8 times ..the area should get 64 times

anonymous · Answer

don't i divide that though by something to find how many times larger? cuz isnt 64 the area or is that my answer to

shubhamsrg · Answer

you're just asked about the ratio of the 2 areas,,it should be 64 only..i.e your ans..

shubhamsrg · Answer

and why will you divide by something/?

anonymous · Answer

i was just wondering if thats the area then you would devide by the original area to find how many 'times' larger it is

shubhamsrg · Answer

thats what i did..
consider earlier area to be 1 unit..
this area gets 64 times as each side gets 8 times
so ratio gives 64 only..

anonymous · Answer

ok thank-you =)

shubhamsrg · Answer

glad to help ^_^