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If a spherical ball is enlarged so that its surface area is 9 times greater than its original surface area, then the original radius was multiplied by _________. Answer
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try a simple experiment r = 1 \[SA = 4\pi \times 1^2\] \[SA = 4 \pi\] then 9 times the SA \[36\pi = 4\pi \times r^2\] \[r^2 = 9\] the radius is 3 so the length of the radius is tripled
ooh i see so wait that was just an example right?
no its the solution but for area the linear ratio is squared radius 1:3 for area becomes 1^2 : 3^2 or 1: 9 volume is linear ratio cubed
I gave you a simple way of solving the problem by letting the radius =1 then multiplying the surface area by 9 and then solving for r
oh ok. thank-you
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