Question

please help...Find the measure of exterior angle A. Show equations and all work that leads to your answer.

Answer 1

http://curriculum.kcdistancelearning.com/courses/GEOMx-HS-WA10/a/assessments/Q-ExteriorAnglesQuiz/Geometry_5.1.16_ExteriorAngleQuiz_FINAL_8q.gif

Answer 2

how do i solve for x

Answer 3

(14x+6)+(6x-3)+(4x+8)+(49)+(3x+30) = 360

How many x's do you have? (Add them up)
add up the simple numbers.
Can you do that?

Answer 4

4 x's, & 123

Answer 5

14x+6x+4x+3x =

how many x's?

Answer 6

4

Answer 7

The number in front of each x is the number of x's 14x is short hand for 14 x's
Now, how many x's?

Answer 8

oh, 27

Answer 9

yes, but write it as 27x
now add up the numbers 6-3+8+49+30

Answer 10

90

Answer 11

OK, what you just did is simplify
(14x+6)+(6x-3)+(4x+8)+(49)+(3x+30) = 360
to
27x+90 = 360

(You added up the terms on the left hand side)

Now subtract 90 from both sides of the equation.

Answer 12

27x + 90 -90 = 360 -90

Answer 13

270

Answer 14

that is only the right hand side. Write down both sides of the equation

Answer 15

if you subtract 90 from both sides you get
27x= 270

Answer 16

Now divide BOTH SIDES by 27

Answer 17

0.1?

Answer 18

\[ \frac{27x}{27} = \frac{270}{27} \]
can you simplify this?

Answer 19

no

Answer 20

what is 27/27?

Answer 21

If you don't know, you can use a calculator

Answer 22

1

Answer 23

That means
\[ \frac{27x}{27} = \frac{270}{27} \]
is
\[ 1x= \frac{270}{27} \]
or because we don't usually write a 1, just
\[ x= \frac{270}{27} \]

now what is 270/27 ?

Answer 24

10

Answer 25

so now you know
x=20

Angle A = 6x-3

to find A, replace x with 10
A= 6*10-3 (we have 6 10's then subtract 3)
What is A?

Answer 26

*x=10 (oops!)

Answer 27

57

Answer 28

Yes. That is the answer to this long question.

Answer 29

thats it?

Answer 30

Yes. You had to know a lot to solve this. You had to know the sum of the exterior angles add up to 360. You had to add up all the terms and solve for x. You then had to use the x to solve for A.

Answer 31

Thank you lol (:

Answer 32

If you have time, here's a video on solving equations
http://www.khanacademy.org/math/algebra/solving-linear-equations/v/solving-equations-2

Khan also has videos on geometry.